[SOLVED] Setting 2 files for grep search in 1 unique variable

NevemTeve · 07-06-2023, 07:59 AM

Don't do that, shell variables aren't meant to store file-contents.

boughtonp · 07-06-2023, 08:29 AM

This appears to be your real problem...

Quote:

Originally Posted by pedropt

... i am parsing the log files for anomalies ...

Quote:

Originally Posted by pedropt

I was thinking in setting just 1 log variable as :

log="/var/log/nginx/access.log*"

but this will include also the gzip files inside nginx logs directory , witch are access.log.2.gz , etc... , and i do not want that .

The answer is to use --exclude, as described in "grep --help" (and man grep):

Code:

grep something /var/log/nginx/access.log* --exclude='*.gz'

Or simply use zgrep to decompress those files before searching them.

(p.s., use "[code]..[/code]" not "[quote]..[/quote]" when posting code.)

pedropt · 07-06-2023, 08:50 AM

Thank you boughtonp and all others that helped on this issue , you guys and many others here are my salvation in many doubts i get when i am building scripts for my server or tools for other stuff here , Linuxquestions is an excellent forum , Thank you all not only for the help but also for the other alternatives solutions and code optimizations you guys help here .

Thank you

MadeInGermany · 07-06-2023, 09:20 AM

One more:

Code:

#!/bin/bash
shopt -s extglob
grep something *.log!(*.gz)

grep -h ....
suppresses the filename: prefixing.