I am writing a simple bash script that will be used to run cron jobs that will manipulate various files with in our file structure. The script is extremely simple but I can't seem to figure out one issue.

When I run the script I get this error. sed: -e expression #1, char 6: unknown option to `s'

Here is the script. The issue I am having is that I am trying to replace . with / in my second argument I am passing to the script.
#!/bin/sh

cfInstance=$1
callto=`echo $2 | sed -e 's/.///g'`
cfMethod=$3
url=$cfInstance$callto$cfMethod

echo $url

You're going to need to escape both special characters.

i.e.

Thank you anomie it worked like a charm.

also, note that you do not have to use "/" as the delimiter. In sed, the delimiter is always the first character after the "s"
so you can do--e.g.:

sed 's*\.*/*g'
(slightly more readable)