hello people, i have been doing some simple scripts for a while but i am facing a situation in witch i don´t have any idea so i request your help:

i have a file full of lines like these one:

http://localhost/repo/pool/main/a/apt/apt_0.7.20.2+lenny2_i386.deb[/url]

i would like to have only the last part "apt_0.7.20.2+lenny2_i386.deb" and then get only the name against a list of package name but that is simpler.

So for my quest i´ve thought two possibilities:
1- finding the last "/" and print the last part
2- finding the fisrt "/" beginning from the end and print the last part

wait any help from you....hugs

I don't know what "against a list of package name" means, but the regex you want for everything after the last / is [^/]*$

Having to escape forward slashes make the regex expression look more complicated.
Lines with '/repo/' are selected. The ending '[/url]' is stripped. Then everything up to the last slash is removed.

The output is saved to the the file packages, which grep uses for the matching pattern list (-f option).