Running a batch command of the same executable when previous is finished

cilbuper · 01-01-2018, 11:18 PM

I have a number of folders with a text file in them and I have a program that accesses this text file and does it's deed as per the instructions inside.

Example:

Here are where the files are located and the program needs to go to the directory where the file is.

/BaseFolder1/WorkFolderA/wfa.txt
/BaseFolder1/WorkFolderB/wfb.txt
/BaseFolder1/WorkFolderC/wfc.txt
/BaseFolder2/WorkFolderQ/wfq.txt
/BaseFolder2/WorkFolderW/wfw.txt
/BaseFolder3/WorkFolderE/wfe.txt
/BaseFolder3/WorkFolderR/wfr.txt

This is what it would look likd if typed it in at the command prompt
/BaseFolder1/WorkFolderA/$>Program_name --input wfa.txt
/BaseFolder1/WorkFolderB/$>Program_name --input wfb.txt

I want to be able to add folders & data files (append them) when I get new ones. I don't care if the program starts over b/c it is fast and skips if it is there already.

So what would a program/batch/script look like that would do this?

astrogeek · 01-02-2018, 01:06 AM

It would probably help if you could provide a better description of exactly what you are trying to do.

From what you have posted with your question I think that you want a script to run continuously or repeatedly, which finds all subdirectories and files along some path matching a pattern like /BaseFolder*/.../wf?.txt, change CWD to that directory and invoke Program_name with the file name. If new directories or files are added it should find them the next time the script is run.

I would suggest using a simple wrapper script (prog_wrapper) which is invoked by a cron rule (cron_wrapper) which uses find to locate the target files and paths.

In pseudo-code, it might look something like this:

Code:

cron wrapper {
     find /BaseFolder* -type f -name wf?.txt -exec prog_wrapper {} ;
}

prog_wrapper {
     cd dirname $1
     Program_name --input basename $1
}

You could implement that as a shell script or in any scripting language with which you are familiar.