[SOLVED] Replace last delimiter BASH

GamezR2EZ · 02-14-2012, 06:12 PM

I have a timecode that I need to change. It is in the format of 00:00:00 It needs to change to 00:00.00

The code I have so far:

Code:

timecode=00:00:00
newtimecode=$(echo $timecode | cut -d: -f1):$(echo $timecode | cut -d: -f2).$(echo $timecode | cut -d: -f3))

Is there a cleaner way to do this? Something like

Code:

newtimecode=$(echo $timecode | sed -e 's/:$//')

Obviously that doesn't work unless the last character is :
Does anyone have a cleaner solution, or should I work with what I have?

sycamorex · 02-14-2012, 06:25 PM

You can try the following:

Code:

sed 's/:/./2' file

It's going to replace the second occurrence of : with .

GamezR2EZ · 02-14-2012, 07:45 PM

That is perfect, thank you!

Not for this problem as I know the variable format, but for future reference is there a way to specify the last occurrence of a character in sed?

grail · 02-14-2012, 10:34 PM

How about you just let bash do its thing:

Code:

newtimecode=${timecode%:*}.${timecode##*:}

sycamorex · 02-15-2012, 01:18 PM

Quote:

Originally Posted by GamezR2EZ

but for future reference is there a way to specify the last occurrence of a character in sed?

I can't think of any generic way to be applicable in every possible scenario. There's always a way if we discuss a specific example.