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i want to read from a file and for every word to do a command.. I use a for loop inside awk for reading all the words inside the file.. Then i want to use grep, but it's a problem because the exit of awk are many results and not one..
for example if file has:
aaaa bbbb cccc dddd eeee
i want to execute:
grep aaaa, grep bbbb...e.t.c
i want to read from a file and for every word to do a command.. I use a for loop inside awk for reading all the words inside the file.. Then i want to use grep, but it's a problem because the exit of awk are many results and not one..
for example if file has:
aaaa bbbb cccc dddd eeee
i want to execute:
grep aaaa, grep bbbb...e.t.c
Any idea??
I don't know if i was clear enough...
you don't need to use a for loop to read records from a file in awk. from what i see your requirement, you can do:
Code:
egrep "aaaa|bbbb" file
will be good if you post your code.(samples of input and output format as well if possible)
Basicly, what i want to do is: i have a file (users.txt) that has the words like this:
aaa bbb ccc ddd eee...
i want the script to take each word and do a command..
I used the command awk to read each word from the file...But then??
Basicly, what i want to do is: i have a file (.txt) that has the names of all the users like this:
aaa bbb ccc ddd eee...
i want the script to take each user and show if he is online or not and the last time he logged in...
I used the command awk to read each user from the file...But then??
Code:
who | awk 'BEGIN {
getline line<"file" #assume only 1 line
n=split(line,user)
}
END{
for (i=1;i<n;i++) {
if ( $1 == user[i]) {
print $1 " logged in"
break
}
}
}
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