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I can tell you why it didn't work too
Your program is definitely not doing what you want it to do.
Code:
int main()
{
// #define EOF 3
// Redefining things like EOF is bad, don't do it.
// Some libs may use EOF and if you redefine it, it might break a lot of things
int a;
a = getchar(); //Note how it's in [ code] and [/ code] tags, it's indented and spaced out
// It not only looks better, but it's simpler to read
while( a != EOF ) // You had = instead of ==, what that would do is assing a the value of EOF
// != is more logical than a! == EOF
// You are not flipping the value of a and then comparing, you are comparing and seeing if they are differnet
// That assignment should always return true, because unless you've used all your computer's memory it won't fail
{
putchar(a);
getchar(a); //Note the fact that it's a all the time, you had c, but I think that was a typo.
}
retrun 0; //It's nice when main returns a value, since when you string programs togeather with && it'll cause the entire chain to fail if it's non 0
//Also a nice way of testing of programs failed or worked
}
I suggest scrapping the code, and doing something else like..
making it stop at a newline (\n)
hi
Yes,c was a typo.
I copyed this exaple from book.
Quote:
Originally posted by teval
while( a != EOF )
// != is more logical than a! == EOF
// You are not flipping the value of a and then comparing, you are comparing and seeing if they are differnet
// That assignment should always return true, because unless you've used all your computer's memory it won't fail
Are you reffering to what would happened if I had
while (a! == EOF) ;
statement?
Is -1 not recognised as EOF because the value that I type in is essentially
a char,and EOF is integer?
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