problem with php logic

veritas · 12-30-2006, 11:27 PM

Hi,

If I leave out the ?name= from logic.php it correctly displays "no name specified." But if I do logic.php?name=Jack it displays wrong name. Same with a bogus value. I tried changing the operator to !=, but the code outputs "name accepted" for any value using this method.

I would appreciate any tips with this.

Code:

<?php
        $var = $_GET["name"];

        if (!$var)
        {
                echo "no name specified";
        }
        else
        {
                if ($var !== ("Jack" || "Jill" || "Ted" || "Sarah"))
                {
                        echo "wrong name";
                }
                else
                {
                        echo "name accepted";
                }
        }
?>

pnellesen · 12-30-2006, 11:51 PM

I think your evaluation needs to be as follows:

Code:

if ($var != "Jack" && $var != "Jill" && $var != "Ted" && $var != "Sarah")

If any of those names is entered, you should see "name accepted"

veritas · 12-31-2006, 12:01 AM

Thanks! That did the trick