print 1 to 100 in a shell script

sleeper0110 · 10-30-2008, 12:03 PM

I need to output the number 1 through 100 in a shell script.
I can't use the c style for loop because the shell (busybox shell) doesn't allow it.

Is there an easy way to do this without typing out all 100 numbers?

I want to use something like:

for i in 1 to 100
do
echo $i
done

rather than
for i in 1 2 3 4 5 ...
do
echo $i
done

Is it possible to do ranges in for loops in regular /bin/sh scripts?

Again, I cannot use c style for loops (for ((a=1; a <=100; a++)))

Thanks

pixellany · 10-30-2008, 12:15 PM

Take a look at the seq command, eg:

for var in `seq 1 5`; do echo $var; done

sleeper0110 · 10-30-2008, 12:48 PM

seq does it for me.
Thanks pixellany!

radoulov · 10-30-2008, 03:51 PM

If your shell supports brace expansion:

Code:

printf "%d\n" {1..100}

nishamathew1980 · 11-02-2008, 04:55 AM

This should do the trick:

for a in `seq 100`
do
echo -n "$a "
done

nishamathew1980 · 11-02-2008, 04:55 AM

Or, you could use this:

for a in {1..100}
do
echo -n "$a "
done

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