passing awk output to $variable for shell script?

NewnanNOC · 10-23-2008, 01:45 PM

Greetings, All.

I'm trying to get some data out of fileA.txt for use as a variable in script.sh. I think I want to use awk, but I'm not sure how to go about it.

fileA.txt:

Code:

1234567890,207699107669,00AABBCCDDB7:1,A

awk:

Code:

awk 'BEGIN { FS = "," } ; { print $1 }' fileA.txt

that gives me 1234567890, which is what I want - but I want to use it in place of $variable in:

Code:

#!/bin/bash

variable=$1

sed "s|aaaa|$variable|g" <template.txt> readyfile.txt

I hope that makes sense, and I'm reasonably sure it's something simple, but I just can seem to get it together...

Any assistance is appreciated!!!

Damoek · 10-23-2008, 01:48 PM

I think all you have to do is set the variable to the awk command in the script itself

variable=$(awk 'BEGIN { FS = "," } ; { print $1 }' /path/to/fileA.txt)

NewnanNOC · 10-23-2008, 01:54 PM

Quote:

Originally Posted by Damoek

I think all you have to do is set the variable to the awk command in the script itself

variable=$(awk 'BEGIN { FS = "," } ; { print $1 }' /path/to/fileA.txt)

That's perfect!!! Thank you so much - I was obiviously trying to over-complicate it...

Thanks again!!

acid_kewpie · 10-23-2008, 02:08 PM

awk isn't my favoured way for such a trivial thing though...

variable=$(cut -d, -f1 fileA.txt)

simpler. easier.