Need help with Bash script

cmfarley19 · 05-10-2007, 09:03 AM

I am a little rusty with my bash skills. I haven't had to do this kind of thing in a little while...
I am trying to parse a text file. It's a log of the capture of some rs-232 communications. The format of the log file is as follows:

Code:

Port opened by process "TEST_PRP.EXE" (PID: 3048)

Request: 05/10/2007 8:36:37 AM.16064

 7C 02 03 00 03 12 00 00 18 DC 7D                  |........Ü}     

Request: 05/10/2007 8:36:39 AM.11364 (+1.9530 seconds)

 7C 02 03 00 03 12 00 00 18 DC 7D                  |........Ü}     

Request: 05/10/2007 8:36:40 AM.67664 (+0.5624 seconds)

 7C 02 03 00 03 12 00 00 18 DC 7D 
...
...
...
Request: 05/10/2007 8:37:12 AM.37664 (+0.2187 seconds)

 7C 02 03 00 03 12 00 F0 F7 C3 7D                  |......ð÷Ã}     

Request: 05/10/2007 8:37:12 AM.61064 (+0.2344 seconds)

 7C 02 03 00 03 12 00 F1 E7 E2 7D                  |......ñçâ}     

Request: 05/10/2007 8:37:13 AM.82964 (+0.2187 seconds)

 7C 02 03 00 03 12 00 00 18 DC 7D                  |........Ü}     

Port closed

I want to just have the hex left behind:

Code:

7C 02 03 00 03 12 00 00 18 DC 7D
7C 02 03 00 03 12 00 00 18 DC 7D
7C 02 03 00 03 12 00 00 18 DC 7D 
...
...
...
7C 02 03 00 03 12 00 F0 F7 C3 7D
7C 02 03 00 03 12 00 F1 E7 E2 7D
7C 02 03 00 03 12 00 00 18 DC 7D

Any help or a nudge in the right direction will be much appreciated.

Chris

0.o · 05-10-2007, 09:12 AM

grep [0-9][A-F] file | cut -b 1-32

cmfarley19 · 05-10-2007, 09:19 AM

Thanks 0.o.
That was the shove I needed.
I modified it to:

Code:

grep [0-9][A-Z] file | cut -d ' ' -f 2-13

To get rid of the leading space.