N-sized array

itz2000 · 11-15-2006, 07:14 AM

Quote:

Originally Posted by dmail

http://www.linuxquestions.org/questi...00#post2502100

What confused me in your post is "double pointer ** to array"
Which I would see as int***

check it to compile it with VS as well... I'm pretty sure it will compile there.

Code:

#include <iostream>
using namespace std;


int main()
{
        int nNum;
        cout << "Enter a number" << endl;
        cin >> nNum;
        int **myArr = new int*[nNum];
}

mtndew · 11-15-2006, 02:39 PM

The pointer method is what I would normally use:

Code:

int * random_array = new int[n];

But for the assignment we were told not to use pointers, I was just interested in knowing why I had points taken off.

It is interesting to know that the C99 standard allows it, however, since I learned C first.

Thanks guys, you answered my question.