Hi,
I am trying to create a directory tree to organize output from a simulation.
I am trying it two different ways but I am having issues with both.
The first is to use the system command with something like this

i and j are ints ()


//this inside a larger for loop
for (i=1;i<imax;i++){


for(j=1;j<jmax;j++){

.....
.....


char dirname1[150],dirname2[150],dirname3[150],dirname4[150],




sprintf(dirname1,"mkdir /home/test/program/directory%d/ \n",k);


if(system(dirname1)==-1){fprintf(stdout,"error in creating dir\n");exit(EXIT_FAILURE);}



sprintf(dirname2,"/home/test/program/directory%d/Data%d \n",k,p);
if(system(dirname2)==-1){fprintf(stdout,"error in creating subdir\n");exit(EXIT_FAILURE);}

...This works (at first) as I cycle though values of i and j but after awhile I get to a certain iteration in i or j the system call starts failing (I dont know why.)


The second way I have tried is with the mkdir function:

sprintf(dirname1,"mkdir /home/test/program/directory%d/ \n",k);

printf("\n%s\n",dirname1);


if(mkdir(dirname1, 0777)==-1){fprintf(stderr," error in writing permissions errno=%d \n",errno);}


sprintf(dirname2,"/home/test/program/directory%d/Data%d \n",k,p);


if(mkdir(dirname2,0777)==-1){fprintf(stdout,"error in creating subdirectory errno=%d\n",errno);exit(EXIT_FAILURE);}


.. The problem here is that mkdir fails and I get errno 2.
If anyone can enlighten me to the correct way to make this directory tree I would greatly appreciate it.

Hi,

errno 2 usually means "No such file or directory". Are you sure the parent directory exists?

Evo2.

Yes,
The directory appears to exist.
For some reason mkdir can't find it.

I believe you were intending to do:

Yes,
you are correct.
I have the code correct in the original program though.

Can you copy and paste the relevant code from your program then (please use the CODE tags)?

you can use the system call mkdir() instead of system(). You can use perror() to print error message after mkdir().
Also you can try system("mkdir -p ......")

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using system is a disciplinary offence.

I would consider firing anyone who uses it without a good explanation.

1 members found this post helpful.