[SOLVED] makefile: change compilation flags by changing target name

mosca · 11-12-2010, 04:16 PM

Hi,
I'm a kind of a newbie with makefiles and I'd like to create a target named "debug" or something similar which will use some special optimization flags useful when debugging (for example -ggdb). At the moment my makefile is neat (which I like) and looks like

Code:

SRC = $(wildcard *.cxx) 
OBJ = $(SRC:.cxx=.o)

INCDIR = -I.
LIB = -lm 
LIBDIR = 

CXX = g++
LD = $(CXX)

CXXFLAGS = -Wextra -Wall -W #-pedantic #-Weffc++
CXXFLAGS += -ansi -pg -ggdb3 #-std=c++0x
CXXFLAGS += -O3 -march=native
LDFLAGS = -ggdb3  -pg 


.SUFFIXES : .o .cxx .hxx

.cxx.o :
	$(CXX) $(CXXFLAGS) $(INCDIR) -c $< -o $*.o

# targets
a.out : $(OBJ)
	$(LD) $(LDFLAGS) $(OBJ) $(LIBDIR) $(LIB) -o $@

files : 
	@echo $(SRC)

all : clean depend a.out

clean :
	/bin/rm -f *.o a.out gmon.out 

depend :
	gccmakedep -- $(INCDIR) -- $(SRC)

Now, I'd like to have a debug target that uses different CXXFLAGS. How can one do that?

Thanks!

jf.argentino · 11-12-2010, 05:16 PM

you can use tests in your makefile like "ifeq"

Code:

ifeq ($(DEBUG), YES)
    CFLAGS+=-g
fi

then call with "make DEBUG=YES"

mosca · 11-13-2010, 06:05 PM

Thanks, that'll work for me.