linux software interrupt

oyoyoOnLinux · 12-05-2001, 03:30 AM

does anyone can tell me how can i do software interrupt in linux...
please help me
thanks

acid_kewpie · 12-05-2001, 04:14 AM

would you not be better of using exceptions instead? much more controlled and easy to handle than interrupts, and i'm not sure you can actually do that even.

isajera · 12-05-2001, 06:18 PM

interrupts are handled almost exclusively in the kernel - if you want a program to use them, you probably need to refer to the driver module for the hardware that you're programming for.

crabboy · 12-05-2001, 06:23 PM

Exceptions can't be used in the place of signals. Signals are a form of interprocess communication where exceptions are not.

There are several different signals that can be caught. In this example the interrupt signal (control C) is caught.
The ignore is put in the handler so we don't get a signal while we are processing the signal. The rule of thumb is to keep the code in the handler as short as possible.

Code:

#include <sys/types.h>
#include <stdio.h>
#include <unistd.h>
#include <signal.h>
#include <sys/wait.h>

static void
sig_int()
{
   /* Signal Interrupt, Captures Control-C  */
   
   if ((int)signal(SIGINT, SIG_IGN) == -1)   /* Ignore ^C  */
      perror("Signal Error");
      
   printf( "Control-C is caught\n\n>" );

   if ((int)signal(SIGINT, sig_int) == -1)
      perror("Signal Error");


   return;

}

main()
{
   char strIn[256];


//   if ((int)signal(SIGINT, SIG_IGN) == -1)   /* Ignore ^C  */
//      perror("Signal Error");

   if ((int)signal(SIGINT, sig_int) == -1)   /* catch ^C  */
      perror("Signal Error");

   while( 1 )
   {
      printf( "> " );
      gets( strIn );
      printf( "%s\n", strIn );
   }

}