ksh syntax error: `(' unexpected

SentralOrigin · 11-10-2010, 02:38 PM

So I am trying to convert my bash script into ksh, and this is what I have in the file so far:

Code:

#!/bin/ksh

login()
{
        if [ "$ALPHA" = "" ]
        then
sendcmd BETA
else
sendcmd "$(xxd -c 32 -g 0 ${ZETA_ZETA} | awk '{print $2}')"
        fi
}

But when I run it:

Code:

$ ./test.sh  
./test.sh[3]: syntax error: `(' unexpected

Am I not seeing something here? I closed all of my () and I don't see any open parentheses...

GrapefruiTgirl · 11-10-2010, 02:42 PM

You need a space between login and () where you define the function.

Also note, if it matters in your code, that in ksh, there is a difference in the way a function works, depending whether or not you define it using the function keyword before the function name. You can see something about this here:
http://www.linuxquestions.org/questi...erence-825846/

SentralOrigin · 11-10-2010, 02:46 PM

Space doesn't help.

I added in some more functions before this line, and there is no problem with them:

Code:

#!/bin/ksh

usage()
{
cat <<EOF

$VERSION

usage: test [-switches] [variables]

EOF
exit 2
}

sendcmd()
{
        echo "$@"
        sleep ${SLEEP_AFTER_CMD}
}

login()
{
        if [ "$ALPHA" = "" ]
        then
sendcmd BETA
else
sendcmd "$(xxd -c 32 -g 0 ${ZETA_ZETA} | awk '{print $2}')"
        fi
}

Code:

$ ./test.sh         
./test.sh[22]: syntax error: `(' unexpected

Still only complains about login()...???

GrapefruiTgirl · 11-10-2010, 02:48 PM

Umm, I think `login` is a keyword or command (I just ran it, and am not sure what it's doing.. EDIT: It's started a login shell in my terminal :/ ) Try using another word?

SentralOrigin · 11-10-2010, 02:54 PM

Thanks...I have to smack myself now

GrapefruiTgirl · 11-10-2010, 02:57 PM

Ehh... Probably most of us have or will encounter this sort of glitch at some point.

Good luck with the rest of the script porting. :-)