how can i check that $1 is number...

DoME69 · 03-08-2009, 09:29 AM

HI ...

how can i check at cshell that $1 is number and not contain letters

Thanks

pixellany · 03-08-2009, 09:36 AM

If the c-shell is like BASH, then numbers are stored as text strings.

echo $1 | grep -v [0-9]

DoME69 · 03-08-2009, 09:48 AM

Thanks...

but this grep can' find

$1 = 98y88

pixellany · 03-08-2009, 10:00 AM

OOPS!!

grep -v [0-9] finds all lines that do not contain any numbers.

grep -v [^0-9] finds all lines that do not contain any characters that are not numbers

Hko · 03-08-2009, 10:07 AM

Quote:

Originally Posted by DoME69

how can i check at cshell that $1 is number and not contain letters

...

Quote:

Originally Posted by DoME69

but this grep can' find

$1 = 98y88

True, but "98y88" isn't a number, as it does contain letters...

DoME69 · 03-08-2009, 01:24 PM

how can i set, if there is letters at $1
set b = 1

else

set b = 0

?

Thanks again.

Hko · 03-08-2009, 02:15 PM

I don't know anything about cshell (sorry).
But here are 3 different ways to do it in bash. Hope this helps you to translate it to cshell.

Code:

if echo $0 | grep -q '^[0-9]*$'; then
    b=1
else
    b=0
fi

Code:

echo $0 | grep '^[0-9]*$' && b=1 || b=0

Code:

echo $0 | grep -qv '^[0-9]*$'
b=$?

DoME69 · 03-08-2009, 02:37 PM

Thanks for your effort
but i need it at cshell

Hko · 03-08-2009, 02:42 PM

Quote:

Originally Posted by DoME69

Thanks for your effort
but i need it at cshell

Shouldn't be too difficult to translate from these bash examples. The grep command can stay the same at least.

AnanthaP · 03-09-2009, 05:55 AM

if expr $1/1 == $1 then number else not a number

Should work at any shell. BTW, at least lookup the exact format for expr.

ATB

End

sureshsujatha · 03-09-2009, 02:08 PM

@AnantaP,
Wont the expression fail if the field inside $1 is not a number?