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Old 11-21-2003, 03:10 PM   #1
Registered: Oct 2003
Posts: 41

Rep: Reputation: 15
grepping last word of output

Hi all,

I am trying to write a script in perl.
It executes df -h and reads the input :
/dev/sda7 688M 45M 608M 7% /scratch
/dev/sda3 981M 17M 915M 2% /tmp
/dev/sda8 494M 282M 187M 61% /usr/vice/cache
/dev/sda5 981M 69M 862M 8% /var

I want to get input in an array ,
where it contains only last field namely -> /scratch, /tmp, /usr/vice/cache, /var

@arr = <xyz>;
takes the whole line as input and I can parse it. But when partition names vary from machines to machines, that ofcourse is not a good idea.

Kindly suggest what to do ???

Rajat Garg
Old 11-21-2003, 03:37 PM   #2
Registered: Mar 2003
Location: Scotland
Distribution: Slackware, RedHat, Debian
Posts: 12,047

Rep: Reputation: 66
I beleive this should work for what you want:
for ($done=1; $done<@array; $done++){
print $array[$done]."\n";
Old 11-25-2003, 08:34 AM   #3
LQ Newbie
Registered: Oct 2003
Posts: 5

Rep: Reputation: 0
you can start with

df | cut -c57-

Last edited by inTrouble?; 11-25-2003 at 08:35 AM.
Old 11-25-2003, 10:41 AM   #4
Registered: Aug 2003
Location: Akron, OH
Distribution: Fedora Core 3
Posts: 185

Rep: Reputation: 30
df -h | awk '{ print $NF }'


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