hi Team,

I have a big log file in the below format

2023-12-18 21:50:47,236 xx.xx.xx.net [http-nio-8080-exec-31] INFO [application=mock-service, traceId=03318e367d976a7f, spanId=0437430f6e81a6e1] a.b.c.d.e.f.g.h.i - Pricing SDR fare value : 4195.20 and current fare : 0 for sdr W7KXK3
2023-12-18 21:50:54,056 xx.xx.xx.net [http-nio-8080-exec-31] INFO [application=mock-service, traceId=03318e367d976a7f, spanId=0437430f6e81a6e1] a.b.c.d.e.f.g.h.i - Pricing SDR fare value : 4195.20 and current fare : 0 for sdr W7KXK3

The requirement is to fetch the values as below
Pricing SDR fare value : 4195.20 and current fare : 0 for sdr W7KXK3
Pricing SDR fare value : 4195.20 and current fare : 0 for sdr W7KXK3

But when i give the
The result have all the lines as below
2023-12-18 21:50:47,236 xx.xx.xx.net [http-nio-8080-exec-31] INFO [application=mock-service, traceId=03318e367d976a7f, spanId=0437430f6e81a6e1] a.b.c.d.e.f.g.h.i - Pricing SDR fare value : 4195.20 and current fare : 0 for sdr W7KXK3

How to get the exact match . I tried all possible combinations of zgrep and sed/awk but the result is printing all the lines.

Any help is appreciated

It looks like the results are as expected. What do you mean by the exact match?

If you are looking to get only the matched string and not the time, date, and other context, then one way is to look at the -o option grep.

If the pattern needs to get more complex look at the -E or -P options.'

As always, see "man grep" for the details.

1 members found this post helpful.

is your friend in this case, assuming lines always contain the same number of fields each time.

Nope, regex rules. See post #2.

Thanks Turbocapitalist. That approach worked here.