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Old 10-30-2003, 02:16 PM   #1
linuxanswer
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Registered: Oct 2003
Distribution: woodY 3.0 stable
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function

void uso(void);

main(int argc, char *argv[]){

if ((argc<2) || (argc>3)){
uso();
exit(0);
}

what it returns? don't understand uso()
 
Old 10-30-2003, 02:18 PM   #2
linuxanswer
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Registered: Oct 2003
Distribution: woodY 3.0 stable
Posts: 61

Original Poster
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sorry sorry i resolve it
 
  


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