[SOLVED] Find and replace multiple instances

grail · 08-16-2010, 08:16 AM

I would probably go with awk for this then:

Code:

 awk '"/usr/X11R6/bin/X" && !/-nolisten tcp/{$0=$0" -nolisten tcp"}1' file

druuna · 08-16-2010, 08:32 AM

Quote:

Originally Posted by grail

I would probably go with awk for this then:

Code:

 awk '"/usr/X11R6/bin/X" && !/-nolisten tcp/{$0=$0" -nolisten tcp"}1' file

Nice, short awk solution!

konsolebox · 08-16-2010, 09:16 AM

Quote:

Originally Posted by grail

I would probably go with awk for this then:

Code:

 awk '"/usr/X11R6/bin/X" && !/-nolisten tcp/{$0=$0" -nolisten tcp"}1' file

Can I ask what's the 1 for? I'm sort of tired to search manuals.

grail · 08-16-2010, 09:21 AM

Quote:

Can I ask what's the 1 for? I'm sort of tired to search manuals.

Sure, always like when I can pass something on

The default action of any true statement is to print, hence 1 is true so print which also equals print $0

konsolebox · 08-16-2010, 09:43 AM

So 1 was actually not directly related to the leading expressions. I was mislead on that. Thanks.

gdavis2287 · 08-16-2010, 12:15 PM

Quote:

Originally Posted by druuna

Hi,

This will fix the possible double -nolisten tcp issue:

sed '/-nolisten tcp/!{s%$:[0-9][0-9]* local /usr/X11R6/bin/X.*$%\1 -nolisten tcp%}' infile

Example run:

Code:

$ cat infile
:0 local /usr/X11R6/bin/X -nobanner
:1 local /usr/X11R6/bin/X
:10 local /usr/X11R6/bin/X -nolisten tcp
:11 local /usr/X11R6/bin/X -nobanner -nolisten tcp
:100 local /usr/X11R6/bin/X -nolisten tcp -nobanner
:1000 local /usr/X11R6/bin/X

$ sed '/-nolisten tcp/!{s%\(:[0-9][0-9]* local /usr/X11R6/bin/X.*\)%\1 -nolisten tcp%}' infile
:0 local /usr/X11R6/bin/X -nobanner -nolisten tcp
:1 local /usr/X11R6/bin/X -nolisten tcp
:10 local /usr/X11R6/bin/X -nolisten tcp
:11 local /usr/X11R6/bin/X -nobanner -nolisten tcp
:100 local /usr/X11R6/bin/X -nolisten tcp -nobanner
:1000 local /usr/X11R6/bin/X -nolisten tcp

Hope this helps.

Works like a charm! One more question. If I wanted to say cat the file and report that there was an entry that was missing the "-nolisten tcp" would a "while read" be best for that?

konsolebox · 08-16-2010, 12:31 PM

You can try this.

Code:

grep ':[0-9]\+ local /usr/X11R6/bin/X' | grep -v -F '-nolisten tcp' >/dev/null && echo 'an entry is missing "-nolisten tcp\"

I wonder when 'while read' started to get popular.. Everything was 'for VAR in ...' back then.

druuna · 08-16-2010, 12:32 PM

Hi,

You want this?

sed -n '/-nolisten tcp/!p' infile

Code:

$ cat infile
:0 local /usr/X11R6/bin/X -nobanner
:1 local /usr/X11R6/bin/X
:10 local /usr/X11R6/bin/X -nolisten tcp
:11 local /usr/X11R6/bin/X -nobanner -nolisten tcp
:100 local /usr/X11R6/bin/X -nolisten tcp -nobanner
:1000 local /usr/X11R6/bin/X

$ sed -n '/-nolisten tcp/!p' infile 
:0 local /usr/X11R6/bin/X -nobanner
:1 local /usr/X11R6/bin/X
:1000 local /usr/X11R6/bin/X

If the /usr/X11R6/bin/X also needs to be part of it:
sed -n '/\/usr\/X11R6\/bin\/X.*-nolisten tcp/!p' infile

Hope this helps.

konsolebox · 08-16-2010, 12:40 PM

finally also an awk style

Code:

awk '/:[0-9]+ local \/usr\/X11R6\/bin\/X/ && !/-nolisten tcp/{ exit (1); }' file || echo 'an entry is missing \"-nolisten tcp\"'

edit: i guess we can put everything inside as one

Code:

awk '/:[0-9]+ local \/usr\/X11R6\/bin\/X/ && !/-nolisten tcp/{ print "an entry is missing -nolisten tcp."; exit; }'