extraction of words

pantera · 10-15-2004, 07:36 AM

i have a character type arrray which contains the datas in following format
abcd:dhdh
i need to find the characters before the ":"
how can i do that
i am using c programming in linux

bahramH · 10-15-2004, 07:52 AM

many possibilities. Here is one which does not use any special function. Let's suppose your array is called "something".

i=0;
while(something[i] != ':' ) i++;

then "i" is your upper limit. You may add additional checks in case your string does not contain any ":"

m00t00 · 10-15-2004, 08:06 AM

strtok(). Read the man page its good.

rustynailz · 10-15-2004, 02:02 PM

strchr() is a better option here, as you don't have to worry about memory allocation, etc like strtok().

The_Nerd · 10-15-2004, 02:28 PM

Code:

char *string="wow:cool:sweet:baby"
char *pt, *pt2;
pt=string;

while(1)
{
	pt2=strchr(pt, ':');
	if (pt2) *pt2=0;

	printf("Parsed string: %s\n", pt);
	if (pt2)
		pt=pt2+1;
	else
		break;
}

Untested... but you get the idea.

You're welcome by the way.