[SOLVED] extract string from right to left

socalheel · 09-05-2013, 02:04 PM

my goal is to only get the domain from an email address.

my problem is there is no standardization to an email address to where there are an equal amount of " . " in the address. is there a way i can extract just the last two words from a string without using "rev"?

example -
from this output:
username@domain1.com
51arouff7n19wbhr@qrqu6wz38tug.a-byiu...nc.domain2.com

i only want to extract
domain1.com
domain2.com

Firerat · 09-05-2013, 02:27 PM

Code:

awk  'BEGIN{FS="[.@]"};{print $(NF-1)"."$NF}'

set Field separators to . and @
print the second to last and last field ( with a . between them )

NF is awk internal var for Number of Fields

firstfire · 09-05-2013, 02:29 PM

Or even shorter:

Code:

awk -F[.@] '{print $(NF-1)"."$NF}' infile

EDIT:

perl alternative:

Code:

perl -ne 'print "$1\n" if /(\w+\.\w+)$/'

socalheel · 09-05-2013, 02:35 PM

awesome stuff guys ... thank you so much!

worked like a champ.