Compiling C++ for x86_64 and get warning: 'cdecl' attribute ignored

fuzzyBuzz · 05-04-2009, 01:36 AM

Hi,

I defined a type of the following form:
typedef void (*myFunc)(int, int) __attribute__((cdecl));
warning: 'cdecl' attribute ignored

When compiling on X86_64 using g++ 4.1.2

Can anyone please explain why am i getting this warning? Is it because cdecl calling convention is not supported on X86_64? If so, what is the calling convention which used?

TIA

clvic · 05-04-2009, 04:34 PM

I think that x86_64 has its own calling convention, that cannot be compared to cdecl.
I'll make a search on the web, I wonder whether all other languages (fortran etc...) now follow this new calling convention.

zekki · 05-25-2012, 09:24 AM

I resume this old thread because I have the same problem.
I read from Wikipedia that on x86_64 gcc uses the System V AMD64 ABI calling convention, instead of cdecl (https://en.wikipedia.org/wiki/X86_ca...em_V_AMD64_ABI).
But how to use it? I can't find any sintax examples...

zekki · 05-27-2012, 11:17 AM

Anyone?