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Old 02-05-2003, 06:33 AM   #1
Registered: Aug 2002
Distribution: RH 7.x
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Unhappy C : Can't type right arrow

I got this funny problem. I've written this code:


26 is the ascii code for the right arrow key, i.e., '->' in its smaller form you can say.
But on running the above line I get nothing at all on the screen .
I'm able to type the left, up and down keys with ascii values something between 24 and 27.

And guess what??, whenever I use fgetc function to read that right arrow from a data file, the return value of this function is -1 instead of 26.

Could anybody enlighten me with his guidance.

Thanks in advance.
Old 02-05-2003, 07:08 AM   #2
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not so funny... ALL of the ascii characters with code number under 32 are control characters... ;-)
chr 26 is the traditional End Of File character... are you working under linux?? This seems a file opened in text mode under dos/windows... as Linux doesn't make any difference between binary and text files... :-) Try to open the file in binary mode ("wb" for writing an "rb" for reading..).

Old 02-06-2003, 12:38 AM   #3
Registered: Aug 2002
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It worked. What a lightening fast reply it was. WOW. But I really don't know how. Please also clarify the following problems:

1) What difference does it make in the return value of fgetc function if the file is opened in ascii and in binary.

2) I thought '/0' with ascii value 0 is used to denote EOF, because it's used to denote end of arrsys and strings. Pleae elaborate on the ascii value 26 being used as EOF in files. ;-)

3) I made a blank file. And ran the following code on it:

int ascii = fgetc(file);

I expected the program not to print anything because it's a blank file. But it prints a "/" on the screen. Why? And what should I do to avoid it.

4) How do I printf the right arrow using it's ascii value 26. ;-))
Old 02-06-2003, 06:54 PM   #4
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Please, I don't want to be unfriendly, but I have Just ONE question... are you sure that you are using gcc under linux??.. ;-) I'm not a moderator at all anyway this is not a C forum.. this is for linux and u are making some c-only questions... I think you'd better read the C FAQ before (for example at url: ) And/Or buy the K&R 2nd edition... And/Or read some newsgroups' archives like the one from comp.lang.c

Please, forgive me Moderator.
For the last time (about this argument):

1) Under linux? None. Under some other os? CR (\r)+LF(\n) = LF(\n) (reading) and LF=CR+LF (writing). \x1a = means EOF (but usually u can keep on reading after this kind of EOF).

2) READ AT LEAST K&R ... C Programming Language, it DOES worth the reading. '\0' is used as a "flag" to terminate arrays (null-terminated strings are only arrays).

3) feof is set only after the first reading that reaches the end of file condition... try this kind of code:

void function()
FILE *fp=fopen("yourfile","rb"); /*just to be sure*/
int c;
while((c=fgetc(fp))!= EOF) {
printf("%c", c);

4) U don't .. and u have to tell WERE you want to print it.. On a text only-terminal, in a X-window application, etc. If u are using text (under linux) I suppose that you have to understand something like ncurses. BTW under c (use #include <ctype.h> if i'm not wrong) there is a function called isprint(c) which tells you what is printable and what is not printable..

Addio (for this argument).
Old 02-15-2003, 08:45 PM   #5
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The note on this forum says questions don't have to be directly related to Linux. It's good to try to keep the rules, though.


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