bash string comparisons wildcard

casperdaghost · 08-08-2012, 02:54 PM

So I have three instances - bincasper32, bincasper41, bincasper42.
They all need to be mapped to port 23471
I wrote a small script that scans the config files after they
are configured, with a few functions.

this works fine

Code:

function ports_bincasper
{
if [[ "$application" == "bincasper41" ]] && [[ "$port" -ne "23471" ]] ;
        then
        echo "               The port to $account is NOT configured correctly"
fi
}

But I would rather not have three seperate functions.
I tried putting a wildcard in the application comparison, but it does not work.
Is there a way for me to do this?

Code:

function ports_bincasper
{
if [[ "$application" == "bincasper*" ]] && [[ "$port" -ne "23471" ]] ;
        then
        echo "               The port to $account is NOT configured correctly"
fi
}

Kustom42 · 08-08-2012, 02:59 PM

Code:

#!/bin/bash

hosts="bincasper32 bincasper41 bincasper42"

for host in $hosts
do
if [[ "$application" == "$host" ]] && [[ "$port" -ne "23471" ]] ;
        then
        echo "               The port to $account is NOT configured correctly"
fi

BAM!

casperdaghost · 08-08-2012, 03:20 PM

KAPOW !!!
it worked,

grail · 08-09-2012, 09:07 AM

Or you could use either parameter substitution or the regex operator:

Code:

if [[ $application =~ bincasper ]] && (( port != 23471 ))

if [[ ${application%%[0-9]*} ==  ]] && (( port != 23471 ))

With the first option you can extend the regex to say it must start (^) with "bincasper" and that it is followed by zero or more (*), one or more (+) or even by exactly 2 ({2}) digits ([0-9] or [[:digit:]]

casperdaghost · 08-10-2012, 12:42 AM

hey - the =~ works great - ( that is what i was originally looking for)

I do not understand the second example - especially the %%

grail · 08-10-2012, 03:30 AM

Search for %% on the following page:

http://tldp.org/LDP/abs/html/paramet...stitution.html