[SOLVED] Bash Scripting: rename bunches of files using source/destination list

bits45 · 08-17-2015, 11:24 AM

I know this is easy, but I'm not getting the syntax quite right.

I have a file which contains this pattern:

path/source_file1 path/destination_file1
path/source_file2 path/destination_file2
path/source_file3 path/destination_file3

I want to loop through that file (let's call it index.txt) and use the move command to move the source file to the destination file. The index.txt file contains over 200 entries.

There's only one source and one destination per line in the inedex.txt file.

I'm trying to loop thru using an array, but I'm not "getting it".

Thanks, I hope I included enough info.

grail · 08-17-2015, 11:49 AM

Please show us what you have so far and where you are stuck?

bits45 · 08-17-2015, 12:16 PM

OH, I'm stuck on Bash 3.2

This is what the file contents might look like:

Code:

cat index.txt 

/source/dir/file /destination/dir/newfile
/source/dir/file1 /destination/dir/newfile1
/source/dir/file2 /destination/dir/newfile2

If I'm saying this correctly, I'm trying to save each row of that index.txt file as an associative array (I think?) so then I could loop thru the index.txt file (array), but "move" the elements from source_file to destination_file for each iteration of the loop. There's no white space in the file names or path, only between the source and destinations themselves.

I thought it might work something like this with the move command once I get the array's elements working right.

Code:

declare -A Array=$(cat index.txt)

for Line in ${Array[@]}
do
  mv ${Line[0]} ${Line[1]}
done

I know this is mucked up.

I know I can read in the file with read, but I suck at that too.

bits45 · 08-17-2015, 01:08 PM

Well, I accomplished the task, but without an array. I know this is too much "work". I shouldn't need awk, right?

Code:

for Line in `<index.txt`; do 

  Source=$(echo $Line | awk '{print $1}')
  Dest=$(echo $Line | awk '{print $2}')
  cp $Source $Dest && echo " Copied $Source to $Dest"

done

HMW · 08-17-2015, 01:26 PM

Edit. OP solved the issue. Awesome!

grail · 08-17-2015, 01:31 PM

HMW ... you really are tired ... hehe

Why not just:

Code:

#!/bin/bash

while read source target; do
    echo -n "Source file: $sourcefile | "
    echo "Target: $target"
done < index.txt

HMW · 08-17-2015, 01:35 PM

Quote:

Originally Posted by grail

HMW ... you really are tired ... hehe

I know. I will refrain from posting now :-P

bits45 · 08-17-2015, 02:43 PM

grail. THANKS!

That worked GREAT, as if you didn't know that already.

I've never used 'read' to create multiple variables.

As expected, it was simpler than I was making it out to be.

Take care!