bash script

pljvaldez · 08-14-2006, 11:55 AM

I'm trying to write a script to automatically take our company phone directory every month and convert it to a palm database file so I have a complete updated directory with me.

Anyway, the script works great, but there's a row of garbage at the top of the file that I'm stumped by.

I've been googling around trying to figure out how to get rid of it and haven't found what I'm looking for. I'm sure there must be a simple awk or bash command that can just whack off the top row of a file, but I'm struggling to find it.

I can live with it, but I was thinking of releasing the phone directory to the rest of the company and would like it to be pretty flawless before I do so.

pljvaldez · 08-14-2006, 12:25 PM

Never mind.

Code:

sed '1d' file.txt > file.csv

burninGpi · 08-14-2006, 12:26 PM

You want to remove the first line of the file? Here's an awk script:

Code:

awk 'FNR>1{print}' file.txt

Andrew Benton · 08-14-2006, 12:27 PM

sed -i '1d' /path/to/filename.txt

osor · 08-14-2006, 12:39 PM

Alternately, sed '2,$p' /path/to/file

Tim Retout · 08-30-2006, 11:05 AM

Yet another alternative:

Code:

tail -n+2 /path/to/file > /path/to/output

Test with something like:

Code:

echo -e "foo\nbar\nbaz" | tail -n+2