Bash read method 'defaults'

wills · 03-28-2011, 03:55 PM

Hi,

I have a script that will ask the operator to specify whether the script should fetch the bits via FTP or SCP:

Code:

# Specify transfer method
echo "[setup]: Please specify file transfer method [ftp] or [scp]:"
 read method

if [ $method == "ftp" ]
	then
		cd $B_DIRECTORY && $LFTP -u $USER,$SECRET $FTP_SERVER -e "pget $PKGS ; exit"
	else
		$SCP "$USER"@"$SSH_SERVER":/"$R_DIRECTORY/$PKGS" ./"$B_DIRECTORY"
	exit
fi

What I'm interested in is to figure out a way to pass along the switch either from the command (e.g. script.sh --ftp) and have the script read that or resort to using the read method by having operator enter it. I'm doing this for the operator that wants to throw in the switches to be more efficient

Any suggestions?

corp769 · 03-28-2011, 04:10 PM

Sure, you can use $1 for a command line parameter, as such:

Code:

#!/bin/bash
ftp1="--ftp"
scp1="--scp"
if [ "$1" = "$ftp1" ]
then
cd $B_DIRECTORY && $LFTP -u $USER,$SECRET $FTP_SERVER -e "pget $PKGS ; exit"
elif [ "$1" = "$scp1" ]
then
$SCP "$USER"@"$SSH_SERVER":/"$R_DIRECTORY/$PKGS" ./"$B_DIRECTORY"
else
echo "Please use either --ftp or --scp"
fi

I don't know if this code will run right away, might need to be tweaked up.

Cheers,

Josh

grail · 03-28-2011, 08:13 PM

Are you passing any other data on the command line currently? If you are you would again need to tweak, but you will get the idea:

Code:

#!/bin/bash

TYPE=''
EXIT=0

if (( $# == 1 ))
then
    TYPE=$1
else
    echo "[setup]: Please specify file transfer method [ftp] or [scp]:"
    read TYPE
fi

case $TYPE in
    --ftp) cd $B_DIRECTORY && $LFTP -u $USER,$SECRET $FTP_SERVER -e "pget $PKGS ; exit";;
    --scp) $SCP "$USER"@"$SSH_SERVER":/"$R_DIRECTORY/$PKGS" ./"$B_DIRECTORY"
    *) echo "Usage: $0 [--ftp|--scp]"; EXIT=1;;
esac

exit $EXIT