Bash: How to remove rows in CSVs where Price column is less than 30
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Bash: How to remove rows in CSVs where Price column is less than 30
I have tons of csv/txt files (~5gb & 300 files). Is there a way to edit all the files where if the price is less than 30, then it will simply remove the rows?
The -F, option tells awk to use a comma as Field Separator. The field is $(NF-1) if you want to parse the column which comes before the last one. That is I count the columns from the last one backward. If you want to count from the first column onward, just do
Nope. Awk cannot edit files in place. You have to use sed with the -i option, but since sed cannot test numeric expressions, you have to find a regular expression matching the price less (or more) than 30. You can try with something like:
Code:
sed -i.bck '/.*,.*,[0-9],.*/d;/.*,.*,[0-2][0-9],.*/d' file.csv
that is you explicitly put all the commas separated fields. The third field will be either a one-digit number between 0 and 9 or a two digit number between 00 and 29. In this way lines with price less than 30 will be deleted.
The -i.bck does a backup copy of the original file with the .bck extension added. This is for safety. Once you've checked the result you can easily remove the backup files by rm *.bck.
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