bash+awk to fix MP3 tags

Yalla-One · 11-06-2005, 09:13 AM

I'm trying to write a small shellscript to fix my MP3 tags, and thanks to Google I've concluded that bash+awk is the way to go.

All my music is in the format 01 - Bruce Springsteen - Born to Run.mp3 (track number - artist - track).
In addition, the mp3 files are always stored in a directory with the album name, so just based on the filename and location, I should be able to get

ARTIST
ALBUM
TRACK
NUMBER

However, my programming capabilities are to say the least rusty, so even my small attempt to start fails with a crude error (Invalid pointer):

Code:

!/bin/sh
CURDIR=`pwd`
ALBUM=`basename "$CURDIR"`
echo $ALBUM

for file in *.mp3 ; do
  echo $file
  awk -F"-" '{ print $1 }' $file
done

Could anyone kindly point me in the right direction for how to get the track number (awk print $1), artist ($2) and track $3 into the right variables so I can then pass it on to id3tag to strip all v1 tags and properly set the v2 tags?

Thanks in advance for any insight

-Y1

Tinkster · 11-06-2005, 12:16 PM

You're quite close :}

Code:

track=`awk -F"-" '{ print $1 }' $file`
artist=`awk -F"-" '{ print $2 }' $file`
title=`awk -F"-" '{ print $3 }' $file`

Cheers,
Tink

Yalla-One · 11-06-2005, 01:42 PM

Hi Tinkster,

Thanks much for your answer!

I tried your suggestion and got the following script:

Code:

#!/bin/sh
CURDIR=`pwd`
ALBUM=`basename "$CURDIR"`
echo $ALBUM

for file in *.mp3 ; do
  TRACK=`awk -F"-" '{ print $1 }' $file`
  ARTIST=`awk -F"-" '{ print $2 }' $file`
  TITLE=`awk -F"-" '{ print $3 }' $file`
  echo "Artist: $ARTIST\nAlbum: $ALBUM\nTitle: $TITLE\nTrack: $TRACK"
done

However, it only gives me:
*** glibc detected *** free(): invalid pointer: 0x08093340 ***
*** glibc detected *** free(): invalid pointer: 0x08093340 ***
*** glibc detected *** free(): invalid pointer: 0x08093340 ***
Artist: \nAlbum: Echo\nTitle: \nTrack:

Is there a bug in awk, or am I still missing a vital part?

Thanks!

Tinkster · 11-07-2005, 12:13 AM

What do you get if you run it from a command-line?

e.g.
ls -1 "01 - Bruce Springsteen - Born to Run.mp3"|awk -F"-" '{ print $1 }'
Similar messages?

Cheers,
Tink

Yalla-One · 11-07-2005, 01:03 AM

Quote:

Originally posted by Tinkster
What do you get if you run it from a command-line?

e.g.
ls -1 "01 - Bruce Springsteen - Born to Run.mp3"|awk -F"-" '{ print $1 }'

That seems to work just fine - the above command prints
01\

And ls -1 "01 - Bruce Springsteen - Born to Run.mp3"|awk -F"-" '{ print $2 }' gives
\ Bruce Springsteen\

I wonder why it fails in the script though... I'm on Slackware 10.2 - could it be an awk problem?

Also - do you have any suggestions on how to cut off the trailing spaces (\ \ ) ?

Thanks again for your patient assistance!

-Y1

schneidz · 11-07-2005, 02:41 PM

Quote:

Originally posted by Yalla-One

Code:

#!/bin/sh
CURDIR=`pwd`
ALBUM=`basename "$CURDIR"`
echo $ALBUM

for file in *.mp3 ; do
  TRACK=`awk -F"-" '{ print $1 }' $file`
  ARTIST=`awk -F"-" '{ print $2 }' $file`
  TITLE=`awk -F"-" '{ print $3 }' $file`
  echo "Artist: $ARTIST\nAlbum: $ALBUM\nTitle: $TITLE\nTrack: $TRACK"
done

i think 'awk' is trying to open '01 - Bruce Springsteen - Born to Run.mp3' and separate any column that is separated with a '-' and print the first column.

i think you should 'ls -1 > track-list.txt' then do a 'for line in `cat track-list.txt`...'

hope this helps,

dustu76 · 11-09-2005, 04:19 AM

Code:

#!/bin/bash

ALBUM=`basename $PWD`
dash="----------------------------"

echo "$dash List of mp3 files in $PWD $dash"
ls -l *.mp3

for i in *.mp3 ; do
        echo "$dash $i $dash"
        OLDIFS=$IFS ; IFS=-
        set `echo "$i" | sed -e 's/ *- */-/g'`
        IFS=$OLDIFS
        echo -e "Artist: $2\nAlbum : $ALBUM\nTitle : ${3%%\.mp3} \nTrack#: $1"
done

HTH

Yalla-One · 11-12-2005, 09:11 AM

That did the trick - thanks much!

Just needed one small adjustment due to spaces in the filename, which was fixed by adding "" around $PWD to get the correct name of the album.

Thanks much to everyone who helped!

-Y1