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Old 04-09-2013, 02:40 PM   #1
dmesserly
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awk print pattern match line and subsequent


Data looks like this:

blahblah
blahblah
pattern data data data
data data data
data data data
pattern data data data
data data data
...
blahblah
blahblah

What I would like to do is match on pattern, print that line and the subsequent data lines, then do not print 'blahblah' to EOF.

If someone can show me how to do this with awk, I would appreciate it!
 
Old 04-09-2013, 04:20 PM   #2
linosaurusroot
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This is a natural job for sed.

sed -n -e '/text_matching_line_to_quit_on/q' -e '/text_matching_first_line_to_show/,$p' filename
 
1 members found this post helpful.
Old 04-09-2013, 05:27 PM   #3
danielbmartin
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With this InFile ...
Code:
blahblah
blahblah
pattern data data data
data data data
data data data
pattern data data data
data data data
blahblah
blahblah
...this awk ...
Code:
awk '{if ($1~"pattern") patseen=1;
      if (patseen && $1!~"blah") print}' $InFile
... produced this result ...
Code:
pattern data data data
data data data
data data data
pattern data data data
data data data
Daniel B. Martin

Last edited by danielbmartin; 04-09-2013 at 05:56 PM. Reason: Tighten the code, slightly
 
  


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