awk inside makefile

RudraB · 12-18-2009, 09:05 AM

I am trying to put a time-stamp in my tar file as:

Code:

distro:
	cp -r LMTO-A LMTO-B lmto/ ASR/ makefile Doc extras
	date>date1
	tstp=`awk '{print $3,$2,$6}' date1`
#	@echo $${tsps}
	make -f extras/makefile clean
	mkdir extras/LMTO-ASR-DISTRO
	cp -r extras/LMTO-A extras/LMTO-B extras/lmto/ extras/ASR/ extras/makefile extras/Doc extras/LMTO-ASR-DISTRO
	tar -zcf extras/lmto-asr-$${tstp}.tar.gz extras/LMTO-ASR-DISTRO
	rm -rf extras/LMTO-ASR-DISTRO

Ithis part is inside a Makefile. It is not working. Where its gong wrong?

paulsm4 · 12-18-2009, 09:42 AM

You can certainly call "awk" from a makefile...

... but you can't use this syntax unless you're actually in the shell:

Quote:

# OK for shell, not OK for inside of a makefile:
tstp=`awk '{print $3,$2,$6}' date1`

SUGGESTIONS:
You might be able to use "bash -c" or "$shell()":

http://www.gnu.org/software/automake...Shell-Function

http://stackoverflow.com/questions/5...kefile-targets

http://www.netbsd.org/docs/pkgsrc/makefile.html

'Hope that helps .. PSM

ntubski · 12-18-2009, 11:51 AM

Every command for a Makefile target is run in a shell. However, every line is run in its own shell.

Code:

tstp=`awk '{print $$3,$$2,$$6}' date1`

Is legal but useless since the assignment to tstp only remains in effect for that line. Note that you need 2 $'s otherwise Make substitutes its own variables.

psaulm4's suggestion of using the $shell() function is probably a better idea, but you could also do this:

Code:

distro:
	cp -r LMTO-A LMTO-B lmto/ ASR/ makefile Doc extras
	tstp=`date | awk '{print $$3,$$2,$$6}'` ;\
		make -f extras/makefile clean ;\
		mkdir extras/LMTO-ASR-DISTRO  ;\
		cp -r extras/LMTO-A extras/LMTO-B extras/lmto/ extras/ASR/ extras/makefile extras/Doc extras/LMTO-ASR-DISTRO ;\
		tar -zcf extras/lmto-asr-$${tstp}.tar.gz extras/LMTO-ASR-DISTRO ;\
		rm -rf extras/LMTO-ASR-DISTRO

The backslashes escape the newlines so all the commands are on a single line and therefore in the same shell.