Hi All,

I am having a problem writing a one liner that will find some text in a script; comment it out; and then insert a new line underneath.

Here is what I mean:

Find: MOZ_LIB_DIR="/usr/lib64"

Insert Comment: #MOZ_LIB_DIR="/usr/lib64"

Add new line: MOZ_LIB_DIR="usr/lib"

Code:

sed 's/MOZ_LIB_DIR=\"/usr/lib64\"/#MOZ_LIB_DIR=\"/usr/lib64\"\nMOZ_LIB_DIR=\"/usr/lib\"' /usr/bin/firefox

Error:

sed: -e expression #1, char 22: unknown option to `s'

I looked at char 22, but I don't see anything wrong. I know the problem has to do with the "", but I don't know how to escape them so that the shell interprets them the way I want.

Thanks for your help,

George

Hi All,

I forgot to mention that the MOZ_LIB_DIR="/usr/lib64" is indented one space in the file.

Thanks,

George

But in which file do you want to do the change? Not in /usr/bin/firefox I hope!

First, you do not have to use / in sed, you can use another marker:

sed 's/pat/pat2/'
can also be written
sed 's?pat?pat2?' or whatever

Because in your sed you didn't escape / in /usr/lib so sed takes it as the marker.

sed 's?MOZ_LIB_DIR="/usr/lib64"?#MOZ_LIB_DIR="/usr/lib64"\nMOZ_LIB_DIR="/usr/lib"?'

Thanks so much NX5000!

I had no idea that you could use other characters as markers when you use sed.

You're welcome

Here are some interesting documents about sed:

http://sed.sourceforge.net/
especially this one for a short introduction:
http://www-106.ibm.com/developerwork...ry/l-sed1.html

And.......

http://www.grymoire.com/Unix/Sed.html