£ symbol and PHP

richlawson · 01-30-2006, 12:43 PM

Hi there,

Not sure if this is the correct section for this question so apologise if it's not.

I've just started out trying to learn PHP and have ran in to an annoying problem. Everytime I enter a '£' symbol in either nano or vi I get this 'Â£'? When the page is viewed via a browser with this symbol present as the wanted '£' symbol I get a black diamond??

Anyone know what the problem is? I'm running fedora core 4 with php 5.0.5-2.1.

Thanks in advance

Hko · 01-30-2006, 12:59 PM

I don't know about vi, but PHP create HTML and in HTML the more correct way to enter such symbols is to use:

Code:

&pound

That will solve the problem with vi as well (for now...

richlawson · 01-30-2006, 05:45 PM

Thanks for the response Hko, that workaround is great.

I've done a bit more digging and it appears that the problem i'm experiencing isn't with my linux + php setup as this fault only occurs when I SSH to the box using putty. I access the box via SSH mostly and hardly ever log on localy.

So I guess this thread is in the wrong section, Mods please could you move somewhere morte appropriate

thanks

matthalliday · 01-30-2006, 10:22 PM

That sort of thing has happened to me before. The problem for me was at I didn't choose the correct keyboard when installing linux.

Just check, maybe that is the problem.

richlawson · 01-31-2006, 11:10 AM

Can't seem to resolve the issue with SSH client but i'm not to fussed to be honest.
Question about the answer Hko gave. How can i get the £ sign next to a variable without a space? I can only get echo statement to print '£ 100' I.E. "&pound $var" if i try to remove the space with "&pound$var" it prints exactly that.

graemef · 01-31-2006, 02:44 PM

How about:

PHP Code:



echo "&pound".$var;

graemef · 01-31-2006, 02:47 PM

Just thought... I think that the special characters should be terminated with a semicolon so maybe the following will also work

PHP Code:



echo "&pound;$var";

richlawson · 02-01-2006, 05:51 AM

Great stuff

Code:

echo "&pound;$var";

works as needed

using full stop gave same result as before.
Thanks a lot.