[SOLVED] [C++] How to access a private member of a class through a friend function of another namespace?

Aquarius_Girl · 02-12-2013, 04:35 AM

Code:

namespace aa
{
    void in ();
};

class x
{
public:
    friend void aa :: in ();

private:
    void pp ()
    {
    }
};

void aa :: in () 
{
    pp ();
}

results in :

Code:

In function ‘void aa::in()’:
error: ‘pp’ was not declared in this scope

Please point out the point that I am missing.

pan64 · 02-12-2013, 05:00 AM

I hope this helps: http://stackoverflow.com/questions/3...er-a-namespace

Aquarius_Girl · 02-12-2013, 05:02 AM

I didn't create an object before calling that private member from the friend function, hence the error.

Quote:

x obj;
obj.pp ();

In that thread, the class there is in namespace (different issue).

pan64 · 02-12-2013, 05:09 AM

so you need to call x::pp() instead of just pp() because pp is a member of x. Next, you cannot call a non-static member without instance, so you either need to make pp static or make an instance of x to be able to call pp

Aquarius_Girl · 02-12-2013, 05:11 AM

I know that and did already realize in my previous post.
It had just slipped out of my mind temporarily.

pan64 · 02-12-2013, 05:14 AM

glad to help you
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and also don't forget to mark SOLVED