Hello,

Please bare with me, I'm rather new.
At the present time I am trying to take a bunch of files in a directory and append the date to the end of them and move them to a different directory.

Here is what I have so far:

#!/bin/sh

DATETIME=`date +%Y%m%d`


mv $1 $1.$DATETIME
mv $1.$DATETIME /home/magicman/done/

At the present time I have to call the script and give it a file. I would like to be able to automatically go to a specific directory, append the date to the end of each file like above and then move the file to the new directory. And then repeat until the directory is empty.

Can anyone help me out regarding this, I'm not that great at programming, but I am learning. Any help would be greatly appreciated! Thanks
John

create another script:
for i in *; do mv-somwhere-with-date $i; done

now read man bash for how to make functions instead separate files.

Raskin,
Thank you for the reply.
I was able to achieve what I wanted to do.
I created another script as you suggested and did this:
for i in /home/magicman/update/*
do
/home/magicman/changename.sh $i
done
And it worked perfectly.
Thanks

I now have a little problem.
I have three scripts that need to run, but depend on which type of files are in a directory.


My three scripts are:
sendjpg
sendmp3
send

In my temp directory /tmp
If I have a file.mp3, run the sendmps, a jpg run sendjpg, and the rest of the files use the send script.

I would like to know how I can place this in a script:
If I have no files, do nothing
If I have mp3, run only sendmp3
If I have a jpg, run only sendjpg
If I have jpg and mp3, run them both.
etc etc.
I'm not sure on how to place this in a script to select the correct action.
John

Well, try 'case':

for i in /tmp/*; do
case $i in
*.mp3)
sendmp3 $i;
;;
*)
send $i;
;;
esac;
done;