[SOLVED] printf not rounding up with %0.f on bash shell (endeavouros)

viriv · 08-03-2020, 05:54 PM

so i wanted to use light for my backlight and use xob to make a nice bar that displays it, but light outputs a number with a comma so i thought i could use printf to round it up but it just outputs a error saying (for example) 1.55 is a invalid number instead of 2, does anyone know why this might be caused?

Keith Hedger · 08-03-2020, 07:24 PM

bash is integer only if you need floats use bc

syg00 · 08-03-2020, 08:10 PM

Works ok if using a bash variable - how are you passing the value to printf ?.

JJJCR · 08-04-2020, 03:37 AM

try:

printf (%0.f,variable)

In C that would print by default the 6 decimal places since you specified floating point.

printf (%0.2f,variable) <-- this would print only 2 decimal places

Or checkout this link at page 5: https://www.cypress.com/file/54441/download

But if you never give the whole code, then we can keep on assuming and guessing.

Good luck!!

pan64 · 08-04-2020, 05:38 AM

in shell without ( ):

Code:

printf "%0.2f" "$variable"

viriv · 08-04-2020, 09:46 AM

i made the mistake of using dots instead of comma's wich bash gave a error for

shruggy · 08-04-2020, 11:51 AM

Quote:

Originally Posted by viriv

i made the mistake of using dots instead of comma's wich bash gave a error for

Code:

$ LC_NUMERIC=de_DE printf %.2f\\n 1.44
bash: printf: 1.44: invalid number
0,00
$ LC_ALL=C printf %.2f\\n 1.44
1.44

viriv · 08-04-2020, 11:53 AM

i found that out the hard way sigh, ddg you have failed me