multiple "screen -d -m" but only one session

samel_tvom · 08-22-2006, 07:32 AM

Hey!

I have this script:

#!/bin/bash

for i in $@
do
screen -d -m btdownloadcurses $i
done

This is nice BUT I would like to have _one_ screen sessions with
multiple windows, containing those btdownloadcurses processes 'cause it much eaiser and faster to switch between them then.

How do I do this?

Thanks!

ciotog · 08-22-2006, 12:58 PM

Just from quickly reading the screen man page, maybe you could adjust the screen line of the script as follows:

Code:

screen -p 0 -d -m btdownloadcurses $i &

samel_tvom · 08-23-2006, 02:37 AM

But I think you have to name the session to reattach to then, since -d -m starts a new session. But yeah, that could work. To first create a screen session than to reattach (but in a detached mode =) ) with -D -m -p $nbr where nbr should increase by one each "for-loop-round".

I will check that out, but I found another way. So if others have this problem I, changed the script, it now looks like this:

Code:

#!/bin/bash

######## BEGIN CONFIGS #####################

#what program to run
program=btdownloadcurses
#dir to put conf files in
dir=/tmp/screenscript

######## END CONFIGS   #####################

# create the dir where we put our config files
if [ ! -d $dir ]; then
        mkdir $dir
fi

# find a file that does not exist
# that will be our conf file
nbr=0
while [ -e $dir/$nbr ]; do
        let nbr++
done

conf=$dir/$nbr
touch $conf

echo source ~/.screenrc >> $conf

win=0
for i in $@; do
        echo screen $win $program $i >> $conf
        let win++
done

# start screen
screen -c $conf -S screenscript