Dear All,

I am using last command on centos system to get users logging information. I want to get information of users logging in today date.

Usually last command output is as follows;

kamran pts/0 10.111.11.135 Fri Nov 7 00:34 still logged in
kamran pts/0 10.111.11.51 Fri Oct 31 20:04 - 04:45 (08:41)

Is there a way if last command just show login users of current date and exclude others from output.
Please help

regards,
kamran

You'll want to write a custom script that will determine today's date and then match it against the last output. Not at all hard.

Dear ember1205,

I have already tried this option by extracting via bash script. But there is a gap between this in 1 specific situation.

I am asssigning date via
Today_Date=$(date | awk '{print $2," ",$3 }') which results in "Nov 7".

Npw see last command output for this date.

kamran pts/0 10.111.11.135 Fri Nov 7 00:34 - 05:01 (04:27)

In above output Nov & 7 are separated by 2 spaces. When I use below command it does not capture this output.

last | grep "Nov 7" ####i.e in script last | grep $Today_Date

Please help on this.

Regards,
Kamran

Use cut instead...

Today_Date=$(date | cut -b5-10)

This will force it to use the exact information so that "Nov 7" will be formatted properly.

Dear ember1205,

Thanks a lot. Problem solved.


Today_Date=$(date | cut -b5-10)

last | grep "$Today_Date"

Putting double quotes around variable results me in exact value which I was expecting.

Thanks ember.

regards,
Kamran

Tell date to produce the same format from the start: