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I have 3 OS, Windows 98, Windows 2000 and Windows XP.
Here is how my two hard disks are divided:
Disk1:
C: Win98 (4 GB)
D: Windows 2000 Pro (4.5 GB)
E: Windows XP (8 GB)
And a lot of space left too in disk 1
Disk 2 is all empty. (20 GB)
I tried to install Red Hat Linux 7.2 in the second hard disk. I used the GRUB boot loader. Linux starts perfectly, but I cannot start my windows anymore!! Why is that??? Do you think it has something to do with the 1024 cylinder rule? Before I installed Linux I could choose among the different Windows I have
Look what it gives me when I select to start windows:
--------------------------------------------------------------------------
Booting 'DOS'
rootnoverify (hd1,4)
chainloader +1
Invalid system disk
Replace the disk, and then press any key
----------------------------------------------------------------------------
What should I do to make it work???? I really want to start working with Linux!!!!
It appears that when you installed red hat that it installed grub in the MBR ( master boot record ) of disk 1. That's why you get grub instead of the boot loader for xp or win2000. The (hd1,4) is the partition hdb5. That's not on disk 1 where your windows os's are located.
Run this command fdisk -l /dev/hda and post the results here. Also, post a copy of your /boot/grub/grub.conf file. If you don't find grub.conf, look for menu.lst. Do you know which boot loader , xp or win2000, was being used before you installed linux?
Linuxcool, what do all these commands do? And where should I type them? Well I don't know what boot loader it is. I installed windows 98, then 2000, then XP. So I guess it should be the boot of XP, no?
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