Bash Help

echat · 07-03-2007, 12:05 PM

Ok, I have not done anything in bash for the past 5 months. Mostly because I have been working c++. I am trying to print an arg list. cant remember how the hell to run through args. I thought it was a for statement but I can't remember if there is an array that holds the agrs. I do remember that the agrs are set up as $1, $2, $3,etc,.... any help would be great.

pixellany · 07-03-2007, 12:16 PM

$1 is "bashese" for the first argument passed in to a script.

One way to iterate thru a set of values is the for loop--e.g.:
for i in <list>
do
something
done

Where <list> can be a literal list, or the output of some other command (using--eg--backtics)

What book do you use for BASH and scripting? Some good references are listed here:
http://www.linuxquestions.org/questi...d.php?t=566095

echat · 07-03-2007, 12:24 PM

I actually don't have any of my scripting books anymore. Lost them in the move.

card-suse · 07-03-2007, 12:37 PM

Quote:

Originally Posted by echat

Ok, I have not done anything in bash for the past 5 months. Mostly because I have been working c++. I am trying to print an arg list. cant remember how the hell to run through args. I thought it was a for statement but I can't remember if there is an array that holds the agrs. I do remember that the agrs are set up as $1, $2, $3,etc,.... any help would be great.

The variable $@ expands all the positional arguments. So

Code:

echo $@

should print all the positional arguments. Is this what you were wanting? If you have options you are trying to parse, then you need to use the getopts construct. Do you want the syntax for that?

echat · 07-03-2007, 12:41 PM

No thank you for that. I just need to run through a for statement. Thank you for this.

Code:

for i in $@; do echo $i; done

^ is just what I needed :]