How do you create an awk script file, myawkmax, that will read 6 numbers, determine which number is the largest one, and then display the largest number.

- the awk script of myawkmax, must include a self-defined function with 6 parameters. No awk built-in functions are allowed to be used in your script.

When test the script with at least following testing cases:
$ ./myawkmax 3 1 2 5 4 6 7
The largest number is 7

$ ./myawkmax -3 -1 -2 -4 -5 -6
The largest number is -1

LQ doesn't answer verbatim homework questions. See LQ Rules: http://www.linuxquestions.org/linux/rules.html

Show your work and ask a specific question and you will receive better answers and help.

4 members found this post helpful.

This should help a lot for beginners,
if not solve your (homework?) problem.

http://www.grymoire.com/Unix/Awk.html

1 members found this post helpful.

Funny!
Giggle giggle giggle..

Hi souchai and welcome to LQ.

szboardstretcher may be correct with their thoughts about a possible homework question. To add to that, my same comments from your other awk question in the Programming forum: LQ members are not here to provide on demand code answers for you. Instead the forum prefers that you attempt to solve your problem and post what you've tried. If you have no idea how to write awk scripts, then ask for help at starting and then post some of your initial attempts.

Hi fanoflq, your first answer offering a helpful link for awk is perfect. Along the lines of the rules cited by szboardstretcher, please note that one of those cites to not post if you do not have something useful to say. So let's stay on topic and see if souchai can provide some additional feedback regarding their needs to accomplish their project.

4 members found this post helpful.

awk is intended for processing input read from standard input or from files whose names are given on the command line.

So with ./myawkmax 3 1 2 5 4 6 7 either you have misunderstood the question or if that is how the question was worded you have been set a real nasty one.