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Old 11-03-2021, 10:33 AM   #1
Faki
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Setting variables in awk according to matching pattern


How can I construct a pattern in `awk` then seh a value for a variable.

I would like to match the following patterns

Code:
^[[:space:]]*(#;!)+[[:space:]]*Mode: org$

^[[:space:]]*(//|@c)[[:space:]]*Mode: org$
 
Old 11-03-2021, 10:34 AM   #2
pan64
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why do you open a new thread for this?
Code:
/pattern/ { var=value }
 
Old 11-03-2021, 11:15 AM   #3
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Basically to make the task simpler rather than reading through a lot of things.
 
Old 11-03-2021, 01:07 PM   #4
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Or throw in a logical OR using the || operator.

Code:
/^[[:space:]]*(#;!)+[[:space:]]*Mode: org$/ \
|| /^[[:space:]]*(\/\/|@c)[[:space:]]*Mode: org$/ \
{ var=value }
Note that inside the pattern the slashes must be escaped.
 
Old 11-03-2021, 10:57 PM   #5
Faki
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Why does it not work like this?

Code:
 charcl='^[[:space:]]*([#;!]+|@c|\/\/)[[:space:]]*' 
 awk -v ccls="$charcl" \
    found { sub(/ccls/,""); print }' "$efile"
But I was unable to remove the comment characters.

Last edited by Faki; 11-04-2021 at 12:19 AM.
 
Old 11-03-2021, 11:08 PM   #6
Turbocapitalist
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Please show the AWK script in which that line is to be found so that the context is known.
 
Old 11-04-2021, 12:18 AM   #7
Faki
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Code:
capture ()
{
 local efile="$1"
 
 local begorg endorg charcl

 charcl='^[[:space:]]*([#;!]+|@c|\/\/)[[:space:]]*' 
 begorg="${charcl}"'Mode: org$'
 endorg="${charcl}"'# End of org$'
 
 awk -v ccls="$charcl" -v bego="$begorg" -v endo="$endorg" \
   '$0 ~ bego { found=1; next }
    $0 ~ endo { found=0; }
    found { sub(/ccls/,""); print }' "$efile"
}
Have also used

Code:
charcl='^[[:space:]]*([#;!]+)[[:space:]]*'
But the comment characters are not being removed.

Last edited by Faki; 11-04-2021 at 12:32 AM.
 
Old 11-04-2021, 01:18 AM   #8
pan64
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when you use sub with a variable you must not use / :
Code:
found { sub(ccls,""); print }
 
Old 11-04-2021, 02:03 AM   #9
Faki
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Works very well, thank so very much. Is there a way to add an empty line between blocks (one block is identified by the lines enclosed within `begorg` and`endorg`)?

Last edited by Faki; 11-04-2021 at 02:05 AM.
 
Old 11-04-2021, 02:16 AM   #10
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Yes, it would be with a print() or printf() function. Add that to the appropriate stanza.
 
Old 11-04-2021, 05:26 AM   #11
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Have used `print ""` to print a blank line. Introduced it on the line checking `endrsc`.

Code:
$0 ~ endrsc { insc=0; print "" }
 
  


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