[SOLVED] set variable in bash

mohitvad · 09-08-2012, 01:51 PM

Hi,

I've problem that i want to print variable with giving a argument (colo) to script and print it . but i am getting an error. Please help me to fix the syntax .Thanks in advance

#!/bin/bash

colo_file="jinda"

echo ${$1_file}

markush · 09-08-2012, 02:00 PM

Hello,

I think you meant this:

Code:

#!/bin/bash

colo_file="jinda"

echo $1_file

Markus

colucix · 09-08-2012, 02:11 PM

Hi Markus!

Maybe I'm wrong, but I think the question is how to retrieve the value of the variable, that is "jinda". I think it's a task of indirect variable reference:

Code:

#!/bin/bash
colo_file="jinda"
varname=$1_file
echo ${!varname}

The variable name is built using the argument, then it's indirectly referenced in the echo statement (uisng the notation introduced in bash version 2).

markush · 09-08-2012, 02:22 PM

Quote:

Originally Posted by colucix

Hi Markus!

Maybe I'm wrong, but I think the question is how to retrieve the value of the variable, that is "jinda". I think it's a task of
...

Well colucix, probably you're right, I misread the question.

Markus

mohitvad · 09-08-2012, 03:34 PM

Hey colucix,

Thanks buddy, it solved the problem. Can i get bit more information about notation/indirect reference to the variable ${!varname}.