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Old 01-08-2018, 05:49 AM   #1
vincix
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Registered: Feb 2011
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sed substitution doubles pattern


Instead of substituting the first pattern, it adds another ".host". I don't understand what I'm missing.

Code:
grep host /etc/varnish/default.vcl
Result:
Code:
.host = "172.31.108.183";
Code:
sed -r "s/(.host = \")[0-9]+.[0-9]+.[0-9]+.[0-9]+(\")/\1\192.10.10.10\2/}" /etc/varnish/default.vcl | grep host
Result:
Code:
.host = ".host = "92.10.10.10";

Last edited by vincix; 01-08-2018 at 06:28 AM.
 
Old 01-08-2018, 06:37 AM   #2
vincix
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Never mind. I was actually trying to escape the first 1 of the "192" group and without realising it, I was actually making the pattern \1 reoccur.
 
Old 01-08-2018, 08:38 AM   #3
pan64
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just a comment: . is a special char, you need to protect it: \. (if you want literal .)

Last edited by pan64; 01-08-2018 at 08:39 AM.
 
Old 01-08-2018, 08:42 AM   #4
vincix
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Yes, I know, you're right. It means any one character.
 
  


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