Hi,

I am new to shell scripts and wrote a very basic script as follows:



#bash script
#Script to search for a file given its filename as a parameter.

if($1 == 0)
print ' No arguments specified ';
exit;
else
find / '!' -type d -name $1 -print0

# End of Script



However I am getting errors when I try to execute the above
script.

Also I am getting "permission denied" message on lots of
folders.

How can I write a script that truly searches the entire drive for
the filename specified without any access problems?


Any help is appreciated.
Thanks
Sharath

>#bash script
instead of this, you should put:
#!/bin/sh (for bash shell)
>#Script to search for a file given its filename as a parameter.
>
>if($1 == 0)
if [$1 == 0]; then
>print ' No arguments specified ';
echo "No arguments specified"
>exit;
exit 0
>else
>find / '!' -type d -name $1 -print0
>
exit 0
># End of Script
This should work (I hope!)
You can also look at this web page for bash scripts:
http://theory.uwinnipeg.ca/UNIXhelp/...hell_help.html

and for your permission denied problems, you can only avoid these problems by being root while executing your script, or change the permissions on all folders! There is no way out!

Hope this help! I am not an expert myself, but I am trying hard!

Cheers
Andree

You can loose the error message if you wish by redirecting STDERR to null in your shell script. So you would use find / '!' -type d -name $1 -print0 2> /dev/null

You say that your script will search for files yeah? Uhm... No... You appear to be searching for directories (-type d) if you want to look for just files then you want -type f

cheers

Jamie...