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Old 07-07-2009, 12:03 AM   #1
ust
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search file


I use the below command to find the file elder than 2 days , it works .

find /var/log -mtime +2 -exec ls -lt {} \;


current result
==============
/var/log/file1
/var/log/file2


But I found that the result is full path , can advise if I want the result is file name only as below , what can i do ?

my desired result
=================
file1
file2
 
Old 07-07-2009, 12:11 AM   #2
your_shadow03
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use this:
basename find /var/log -mtime +2 -exec ls -lt {} \;
 
Old 07-07-2009, 12:13 AM   #3
jschiwal
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To format the output of find in various ways, look at using -printf.
find /var/log -mtime +2 -printf '%f\n'
 
Old 07-07-2009, 12:15 AM   #4
pixellany
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Pipe the result into SED....

eg :

sed 's%^.*/%%'

Replaces any number of characters from the beginning of the line, up to and including the last instance of "/", with an empty character. "%" is used as the delimiter to allow "/" to be in the Regex.

This will do the same thing:
sed 's/^.*\///'
 
  


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