script queries

LYC · 04-02-2015, 02:51 AM

Hi,

Below is the output of the "date" command:
Thu Apr 2 16:07:59 SGT 2015

After assigning the output to a parameter as follows:
DATE=`date`

The output has changed when "echo $DATE":
Thu Apr 2 16:09:40 SGT 2015
^^

The "2" has moved forward.

I don't want the "2" to move forward, please advise how to go about it.

Thanks in advance.

pan64 · 04-02-2015, 02:55 AM

would be nice to use [code]here comes your example[/code] to keep formatting. Otherwise noone will see your problem
Try:

Code:

echo "$DATE"
(instead of echo $DATE)

LYC · 04-02-2015, 03:37 AM

Hi,

Thanks it is working.

Another query about date:

I use the following to replace the "0" with space in front of the date:

Code:

DATE=`date +"a %b %d" | sed 's/0/ /'`

The output produced "Thu Apr 2" instead of "Thu Apr 02". The result is what I wanted but it will also remove "20" to "2". That is "Thu Apr 20" becomes "Thu Apr 2", the result is not I wanted.

Is there a way to work around?

syg00 · 04-02-2015, 03:40 AM

Check the format modifier you are using - you asked for the leading zero.

pan64 · 04-02-2015, 03:43 AM

sure, you need to replace <space>-and-0: sed 's/ 0/ /' for example, but you can also try: date +%-d
(if you really want to say thanks just click on yes)