replace the nth column date as MM/DD/YYYY
Hi,
I need some unix command to replace the following thing.
cat test.dat
1234|test|8/19/2009||test
1234|test|8/9/09|8/21/2009|test
1234|test||8/1/09|test
after processing
1234|test|08/19/2009||test
1234|test|08/09/2009|08/21/2009|test
1234|test||08/01/2009|test
Last edited by anshaa; 08-13-2012 at 03:26 AM.
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